Question

A bullet of mass 100 gm is
projected from a loaded gun with
one bullet of total mass 10.1 kg at an
angle of 60° with the horizontal
direction. If the gun recoils back with
a velocity of 0.02 m/s, calculate the
velocity of the bullet.​

Answer 1

Answer:

Recoil in of the gun happens due to conservation of linear momentum.

Mass of gun=20kg

Mass of bullet=100g=100/1000=0.1kg

Recoil velocity =v1

Bullet fired with initial velocity, v2=100m/s

Initially the gun is at rest.

Thus initial velocity v=0

Total initial momentum of gun and bullet =(m1+m2) v=0

Total momentum of gun and bullet after firing =m1v1 + m2v2=20v1+0.1×100

20v1 + 10

Law of conservation of linear momentum :

Total momentum after firing = total momentum before firing.

20v1 + 10=0

v1=-10/20=-0.5m/s

Recoil velocity =-0. 5m/s

The negative sign indicates the gun recoil backwards.