A bullet of mass 100 gram is fired from a gun of mass 20 kg with a velocity of 50 metre per second identify the velocity of recoil of the gun
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Answer:
0.25 m/s
Explanation:
As V = mv/M
where m = mass of bullet , v = velocity of bullet and M = mass of gun
And V = recoil velocity now we will convert mass of bullet into kg
m=0.1 kg
Therefore
V = mv / M
V = 0.1×50 / 20
V = 5/20
therefore V = 0.25 m / second
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