Question

A bullet of mass 100 gram is fired from a gun of mass 20 kg with a velocity of 100 metre per second identify the velocity of recoil of the gun.​

Answer 1

Answer:

-0.5ms^-1

Explanation:

Mass of bullet, m=100g =100/1000kg =1/10kg

Velocity of a bullet, v =100ms^-1

Mass of gun, M=20kg

Let recoil velocity of gun =V

Before firing, the system (gun + bullet) is at rest,

therefore, initial momentum if the system =0

Final momentum of the system = momentum of the bullet +momentum of gun

=mv+MV =1/10 ×100 +20V = 10 + 20V

Applying law of conservation of momentum, Final momentum = initial momentum

i.e., 10+20V = 0

20V= -10

or, V=-10/20 =0.5ms^-1.

Negative sign shows that the direction of recoil velocity of the gun is opposite to the direction of the velocity of the bullet.

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