A bullet of mass 100 kilogram is fired from the rifile of mass 200 kilogram with the speed of 50 m/s calculate the recoil velocity of gun
Answers
Answered by
0
I think that there is some mistake in your question
Answer:
Mass of bullet, m=100g=
1000
100
kg=
10
1
kg
Velocity of bullet, v=100ms
−1
Mass of gun, M=20kg
Let recoil velocity of gun =V
Before firing, the system (gun+bullet) is at rest, therefore, initial momentum of the system =0
Final momentum of the system = momentum of bullet + momentum of gun
=mv+MV=
10
1
×100+20V=10+20V
Applying law of conservation of momentum, Final momentum = Initial momentum
i.e., 10+20V=0
20V=−10
or V=−
20
10
=−0.5ms
−1
.
Negative sign shows that the direction of recoil velocity of the gun is opposite to the direction of the velocity of the bullet.
Hope it helps
Answered by
0
Answer:-
- Mass of bullet=m1=100g=0.1kg
Fact:-
No bullet weighs 100kg
- Mass of Rifle=200kg=m2
- initial velocity=u=50m/s
- recoil velocity=v=?
We know
Recoil velocity is 0.02m/s.
Similar questions