A bullet of mass 100g is fired at a velocity of 100m/s into a wooden block of mass 900g.If the bullet gets embedded into the block ,then the velocity of system is?
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intial velocity of bullet is u1=100 m s-1
intial velocity of block is u2=0
mass of bullet m=0.1 kg
mass of block M=0.9 kg
by linear conservation of momentunm
mu1=(M+m)v
v=(0.1)(100)/(01+0.9)=10/1=10 m s-1
therefore velocity of system is 10 ms-1
intial velocity of block is u2=0
mass of bullet m=0.1 kg
mass of block M=0.9 kg
by linear conservation of momentunm
mu1=(M+m)v
v=(0.1)(100)/(01+0.9)=10/1=10 m s-1
therefore velocity of system is 10 ms-1
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Answer:
Explanation:
intial velocity of bullet is u1=100 m s-1
intial velocity of block is u2=0
mass of bullet m=0.1 kg
mass of block M=0.9 kg
by linear conservation of momentunm
mu1=(M+m)v
v=(0.1)(100)/(01+0.9)=10/1=10 m s-1
therefore velocity of system is 10 ms-1
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