Question

A bullet of mass 100g is fired from a gun of mass 20 kg with a velocity of 100m/s.Calculate the velocity of recoiling of gun

Answer 1

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Answer 2

Answer:

A bullet of mass 100g is fired from a gun of mass 20 kg with a velocity of 100m/s, the velocity of recoiling of the gun is 0.5m/s

Explanation:

• The momentum of a system is conserved when no external force is acting on it, that is

        initial momentum $P_{i}$ = final momentum $P_{f}$

from the question, we have

mass of the bullet $m_{b} =100g=0.1kg$

mass of the gun $m_{g} =20kg$

the velocity of the bullet after fired $v_{b} =100m/s$

the initial momentum of the system $P_{i}=0$

(since the system is initially at rest)

the final momentum of the system $P_{f} =m_{b} v_{b} +m_{g} v_{g}$

⇒$0=m_{b} v_{b} +m_{g} v_{g}$

⇒$0=0.1*100+20*v_{g}$

⇒

$-10=20v_{g} \\v_{g} =-0.5m/s$

the recoil velocity of the gun is $v_{g} =0.5m/s$

its direction is opposite to that of the motion of the bullet so put a negative sign