Question

a bullet of mass 100g is fired from a gun of mass 20kg with the speed of 50 ms-1 calculate the recoil velocity of the gun.​

Answer 1

Mass of bullet, m=100g= 100/1000 kg

=1/10kg

Velocity of bullet, v=50ms-¹

Mass of gun, M=20kg

Before firing, the system (gun+bullet) is at rest, therefore, initial momentum of the system =0

Final momentum of the system = momentum of bullet + momentum of gun

=mv+MV= 1/10×50×20V

=5+20v

Applying law of conservation of momentum, Final momentum = Initial momentum

5+20v = 0

20v = -5

v = -5/20

v = 0.25m/s-¹

Negative sign shows that the direction of recoil velocity of the gun is opposite to the direction of the velocity of the bullet.

Answered By

toppr

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