Question

A bullet of mass 100g is fired with a velocity of 10ms from a gun of mass 1 kg . find the ratio of the kinetic energy of the bullet to that of the gun

Answer 1

Answer:

10:1

Explanation:

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Answer 2

Answer:

A bullet of mass 100g is fired with a velocity of 10ms from a gun of mass 1kg, the ratio of the kinetic energy of the bullet to that of the gun is 5/0.5=10

Explanation:

• Kinetic energy is the energy of a moving body

• for a body of mass (m) moving with velocity (v) kinetic energy is given by the formula

               $KE=\frac{1}{2} mv^{2}$

From the question, it is given that

mass of the bullet $m_{b} =100g=0.1kg$

the velocity of the bullet $v_{b} =10m/s$

therefore kinetic energy of the bullet,

$KE_{b} =\frac{1}{2}*0.1*10*10=5J$

mass of the gun $m_{g} =1kg$

using momentum conservation we can write

initial momentum= final momentum

⇒$0=m_{b} v_{b} +m_{g} v_{g}$

⇒

$0=0.1*10+1*v_{g}\\ v_{g}=1m/s$

the velocity of the gun $v=1m/s$

therefore kinetic energy of the gun,

$KE_{g} =\frac{1}{2}*1*1*1=0.5J$

the ratio of the kinetic energy of the bullet to that of the gun is

$KE_{b} /KE_{g} =5/0.5=10$