Physics, asked by arunthunduarun8994, 1 year ago

A bullet of mass 100g is fired with velocity 10m/s from a gun of mass 1kg.The ratio of kinetic energy of bullet to that of gun

Answers

Answered by shreyasharidas6
6

You need to know a few things to answer this, and make some assumptions.

kinetic energy = 1/2 m *v^2

Momentum = m *v

If we assume the gun is not fixed in any way ( say hanging from strings) we can assume that the effective mass is 10 kg.

Because, under simple Newtonian mechanics, momentum must be conserved, m * v ( gun ) = m*v ( bullet), so the net momentum of the system remains zero.

So from the weights, it is easy to figure out the relative velocities of the two parts of the system.

So we know now all you need to do is plug that velocity into the formulae for kinetic energy.

I’m not going to do the sums for you- you need to do your own homework to understand it!

Answered by sachinmahawali10
0

Explanation:

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