Question

a bullet of mass 100g is horizontally fired with the velocity of 150ms from a pistol of mass 2 kg . What is the recoil velocity of gun​

Answer 1

Answer:

1.5 m/s in opposite direction

Step-by-step explanation:

Let the direction in which the bullet is fired be positive.

Therefore,

Mass of Bullet(m)=20 grams=0.02 kg

Mass of Pistol(M)=2 kg

Initial Velocity of Bullet(u)=0 m/s

Initial Velocity of Pistol(U)=0 m/s

Final Velocity of Bullet(v)=150 m/s

Final Velocity of Pistol(V)= Recoil Velocity of Bullet = ?

According to the Law of Conservation of Momentum,

mu + MU = mv + MV

(0.02)(0) + (2)(0) = (0.02)(150) + (2)(V)

0 + 0 = 3 + 2V

-3/2 = V

V = -1.5 m/s

Therefore, the recoil velocity of the pistol will be 1.5 m/s in the opposite direction.(As the sign is negative)