A bullet of mass 100g is moving with a velocity 500 m/s . Find the work done to stop it.
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Kinetic energy (initial) of the object = 1/2 × mv²
m = 100 g = 0.1 kg
v = 500 m/s
=> v² = 2,50,000
So, kinetic energy (initial) of the object = 1/2 × 0.1 × 2,50,000
= 12,500 Joules.
Now, since the bullet is to be stopped, its final velocity will become zero. Then, the kinetic energy will also be zero
=> kinetic energy (final) = 0
Now, work done = ∆K
=> Work done = kinetic energy (final) - kinetic energy (initial)
=> Work done = 0 - 12,500 Joules.
=> Work done = -(12,500)Joules.
The answer is in negative because the angle between the applied force and. object is 180°.
Answer :- -(12,500) Joules.
m = 100 g = 0.1 kg
v = 500 m/s
=> v² = 2,50,000
So, kinetic energy (initial) of the object = 1/2 × 0.1 × 2,50,000
= 12,500 Joules.
Now, since the bullet is to be stopped, its final velocity will become zero. Then, the kinetic energy will also be zero
=> kinetic energy (final) = 0
Now, work done = ∆K
=> Work done = kinetic energy (final) - kinetic energy (initial)
=> Work done = 0 - 12,500 Joules.
=> Work done = -(12,500)Joules.
The answer is in negative because the angle between the applied force and. object is 180°.
Answer :- -(12,500) Joules.
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