Question

A bullet of mass 10g hits a target and penetrates 2cm into it. If the average resistanceoffered by the target is 100N then the velocity with which the bullet hits the target is

Answer 1

Answer: 20ms-1

Explanation:

Here the work done is,

W=Fs

= 100N*2/100. (Here distance is in cm so convert it to m)

=2J

So, KE must be equal to work done.

1/2mv^2 = 2

V^2= 1/2*2*10/1000 ( here mass is in gram, so convert it to kg)

V= sqrt400

V = 20ms-1

Answer 2

Answer:

20ms- is answer. okokokokokokokokok