Question

A bullet of mass 10g is fired at a speed of 200m/s from a gun of mass 2.0 kg. The recoil velocity of the gun is

Answer 1

Answer:

Conservation of linear momentum gives,

m

1

v

1

+m

2

v

2

=0

m

1

v

1

=−m

2

v

2

v

1

=

m

1

−m

2

v

2

Given, m

1

=10g=(

1000

10

)kg,

m

2

=1 kg,

v

2

=−5m/s

∴v

1

=

10/1000

+1×5

or v

1

=500m/s.