A bullet of mass 10g is fired at a speed of 400m/s from a gun of mass 4kg.what is the recoil velocity of a gun?
Answers
Answered by
26
Hi,
Solution)
Given-
Mass of the gun(m ᵃ) = 4 kg
Mass of the bullet(m ᵇ) = 10 g
Velocity of gun (v ᵃ) = x
Velocity of bullet (v ᵇ) = 400 m/s
Recoil Velocity
m ᵃ * v ᵃ = m ᵇ * v ᵇ
Substituting Values in above equation
4 * x = 0.01 * 400
4 * x = 4
x = 4/4
x = 1
Answer) The recoil velocity is 1 m/s because here no external force is acted hence momentum of gun+bullet is conserved
initial momentum = finial momentum.
THANK YOU
Solution)
Given-
Mass of the gun(m ᵃ) = 4 kg
Mass of the bullet(m ᵇ) = 10 g
Velocity of gun (v ᵃ) = x
Velocity of bullet (v ᵇ) = 400 m/s
Recoil Velocity
m ᵃ * v ᵃ = m ᵇ * v ᵇ
Substituting Values in above equation
4 * x = 0.01 * 400
4 * x = 4
x = 4/4
x = 1
Answer) The recoil velocity is 1 m/s because here no external force is acted hence momentum of gun+bullet is conserved
initial momentum = finial momentum.
THANK YOU
Answered by
3
Given-
Mass of the gun(m ᵃ) = 4 kg
Mass of the bullet(m ᵇ) = 10 g
Velocity of gun (v ᵃ) = x
Velocity of bullet (v ᵇ) = 400 m/s
Recoil Velocity
m ᵃ * v ᵃ = m ᵇ * v ᵇ
Substituting Values in above equation
4 * x = 0.01 * 400
4 * x = 4
x = 4/4
x = 1
Answer) The recoil velocity is 1 m/s because here no external force is acted hence momentum of gun+bullet is conserved
initial momentum = finial momentum.
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