Science, asked by AmieSins, 6 months ago

A BULLET OF MASS 10G IS FIRED FROM MASS 6KG WITH A VELOCITY OF 300m/s .CALCULATE THE RECOIL VELOCITY OF GUN​.

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Answers

Answered by rishabhsharma50
2

Answer:

Given:-

Mass of bullet is 10g .

Mass of gun is 6kg.

Velocity of bullet is 300m/s.

To Find:-

The recoil velocity of gun .

Formula Used:-

We will make use of concept of law of conservation of momentum.

\large{\underline{\boxed{\red{\tt{\dag m_1v_1+m_2v_2=m_1u_1+m_2u_2.}}}}}

†m

1

v

1

+m

2

v

2

=m

1

u

1

+m

2

u

2

.

Calculation:-

Here as per given data ,

\tt{ m_1=10g \:and\: m_2=6kg}m

1

=10gandm

2

=6kg

\tt{v_1=300m/s \:and\:v_2=?}v

1

=300m/sandv

2

=?

\tt{u_1=u_2=0m/s.}u

1

=u

2

=0m/s.

On putting the values in power formula stated,

\tt{\implies m_1u_1+m_2u_2=m_1v_1+m_2v_2 }⟹m

1

u

1

+m

2

u

2

=m

1

v

1

+m

2

v

2

\tt{\implies 10g\times0+6\times 0=10g\times 300+6kg\times v_2}⟹10g×0+6×0=10g×300+6kg×v

2

\tt{\implies 0 = 0.01\times300+6v_2 }⟹0=0.01×300+6v

2

\tt{\implies 6v_2=(-3)}⟹6v

2

=(−3)

\tt{\implies v_2=\dfrac{\cancel{-3}}{\cancel{6}}}⟹v

2

=

6

−3

\underline{\boxed{\red{\tt{\longmapsto v_2=-0.5m/s}}}}

⟼v

2

=−0.5m/s

Hence the recoil velocity of gun is 0.5 m/s.

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