A BULLET OF MASS 10G IS FIRED FROM MASS 6KG WITH A VELOCITY OF 300m/s .CALCULATE THE RECOIL VELOCITY OF GUN.
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Answers
Answer:
Given:-
Mass of bullet is 10g .
Mass of gun is 6kg.
Velocity of bullet is 300m/s.
To Find:-
The recoil velocity of gun .
Formula Used:-
We will make use of concept of law of conservation of momentum.
\large{\underline{\boxed{\red{\tt{\dag m_1v_1+m_2v_2=m_1u_1+m_2u_2.}}}}}
†m
1
v
1
+m
2
v
2
=m
1
u
1
+m
2
u
2
.
Calculation:-
Here as per given data ,
\tt{ m_1=10g \:and\: m_2=6kg}m
1
=10gandm
2
=6kg
\tt{v_1=300m/s \:and\:v_2=?}v
1
=300m/sandv
2
=?
\tt{u_1=u_2=0m/s.}u
1
=u
2
=0m/s.
On putting the values in power formula stated,
\tt{\implies m_1u_1+m_2u_2=m_1v_1+m_2v_2 }⟹m
1
u
1
+m
2
u
2
=m
1
v
1
+m
2
v
2
\tt{\implies 10g\times0+6\times 0=10g\times 300+6kg\times v_2}⟹10g×0+6×0=10g×300+6kg×v
2
\tt{\implies 0 = 0.01\times300+6v_2 }⟹0=0.01×300+6v
2
\tt{\implies 6v_2=(-3)}⟹6v
2
=(−3)
\tt{\implies v_2=\dfrac{\cancel{-3}}{\cancel{6}}}⟹v
2
=
6
−3
\underline{\boxed{\red{\tt{\longmapsto v_2=-0.5m/s}}}}
⟼v
2
=−0.5m/s
Hence the recoil velocity of gun is 0.5 m/s.