Question

A bullet of mass 10g is fired horizontally with velocity 200m/s from a pistol of mass 3 kg calculate recoil velocity of pistol​

Answer 1

Answer:

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Answer 2

Answer:

Explanation:

• mass of bullet = M₁ = 10 g = 0.01 kg
• velocity of gun = V₁=200 m/s
• mass of gun= M₂= 3 kg
• velocity of gun = recoil velocity= V₂= ?
• now as initial momentum = 0
• so according to law of conservation of momentum final momentum will be equal to 0.
• m₁v₁+m₂v₂=0
• m₁v₁=  -m₂v₂
• 0.01×200=  -3×v₂
• v₂=  -2/3m/s
• v₂= recoil velocity = -2/3 m/s = -0.67 m/s.

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