A bullet of mass 10g is fired with a rifle. The bullet takes 0.03s to move though its barrel and leaes it with a velocity of 300m/s. what is the force exerted on the bullet by the rifle
Answers
Answered by
58
Ans.
Given below are the:
Mass of the bullet (m) = 10g = 0.01 kg
Time taken by the bullet through its barrel (t) = 0.03s
The velocity at which the bullet leaves from the barrel (v) = 300 m/s
U=0
V = u + a*t
300 = 0+a*0.03
A = 10000
Now,
F = m*a = 0.01 * 10000
= 100N
Given below are the:
Mass of the bullet (m) = 10g = 0.01 kg
Time taken by the bullet through its barrel (t) = 0.03s
The velocity at which the bullet leaves from the barrel (v) = 300 m/s
U=0
V = u + a*t
300 = 0+a*0.03
A = 10000
Now,
F = m*a = 0.01 * 10000
= 100N
Similar questions