Question

a bullet of mass 10g is horizontally fired with a velocity of 10m/s from a gun of mass 10kg.find the linear momentum of gun when moves backward.


please answer fast​

Answer 1

Answer:

 

Initial momentum of the system including the gun and the bullet = 0  

Final momentum of the system = momentum of the gun + momentum of the bullet = Mv/ + mv  

(v/ is the recoil velocity of the gun)  

Applying conservation of linear momentum,  

0 = Mv/ + mv  

Implies, v/ = -(mv)/M

The negative sign indicates that the direction of velocity of the gun is opposite to the direction of velocity of the bullet.

m =10g =0.01kg

mass of gun M= 6kg

velocity of bullet = 300m/s

v/ = -(mv)/M

  = -(0.01 * 300)/6

 = 3/6= -0.5 m/s