Question

A bullet of mass 10g is horizontally fired with a velocity 100m/s from a gun of mass 10kg. The gun will move backward with linear momentum:
1.) 10 kg m/s
2.) 1 kg m/s
3.) 5 kg m/s
4.) 2 kg m/s

Answer 1

Answer:

Given:

Mas of bullet, M

b

=10g

Velocity of bullet, V

b

=150ms

−1

Mass of pistol, M

g

=2kg

Due to the law of conservation of momentum, the momentum of the bullet is equal to the recoil of the gun. So the sum of the momentum of both the objects is equal to zero.

M

b

V

b

=−M

g

V

g

.

⟹V

g

=−

M

g

M

b

V

b

=−

2

0.01×150

=0.75ms

−1

.

−ve sign is ignored in the final answer as it denotes the direction of the velocity of the pistol.

I hope it is helpful for you

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