A bullet of mass 10g is horizontally fired with a velocity of 100m/s from a gum of mass 10 kg. The gun will move backward with linear momentum
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Answered by
23
Heya
Here is ur ans
Momentum=mass*Velocity
Momemtum before gun is fired =momentum of gun after firing +momentum of bullet firing
100g=0.1kg
By conservation of momentum
(10x0.1kg)*0m/s
10kg * Vm/s +(0.1Kg *100m/s
0=10V +10
V= -1m/s
Here is ur ans
Momentum=mass*Velocity
Momemtum before gun is fired =momentum of gun after firing +momentum of bullet firing
100g=0.1kg
By conservation of momentum
(10x0.1kg)*0m/s
10kg * Vm/s +(0.1Kg *100m/s
0=10V +10
V= -1m/s
Answered by
20
According to conservation of momentum
Momentum of system =momentum of gun + momentum of bullet
0= momentum of gun + 0.01•100
0=momentum of gun + 1kgm/s
-momentum of gun=1kgm/s
Momentum of gun =-1kgm/s
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