Question

A bullet of mass 10g is moving with velocity 400m/s and gets embedded in a freely suspended block of mass 900g. find the velocity of the block. PLS ANSWER FAST

Answer 1

Solution :

Here, Mass of the bullet,

<br>

kg <br> =0.01 kg <br> And, Velocity of the bullet,

=400 m/s <br> So, Momentum of bullet=

<br>

…….(1) <br> Now, this bullet of mass 10 g gets embedded into a wooden block of mass 900 g . So ,the mass of wooden blockk alongwith the embedded bullet will become 900+10=910 g. Thus, <br> Mass of wooden block+Bullet,

<br> =910 g <br>

kg <br> =0.91 kg <br> And, Velocity of wooden block+bullet,

(To be calculated) <br> So, Momentum of wooden block+bullet=

<br>

kg.m/s...(2) <br> Now, according to the law of conservation of momentum, the two momenta as given by equations (1) and (2) should be equal. <br> So,

<br> or 0.01

<br> And,

<br> =4.4 m/s <br> Thus, the velocity acquired by the wooden block (having the bullet embedded in it) is 4.4 metres per second.

Answer 2

Explanation:

answer :-v=4.39m/s

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