a bullet of mass 10g is shot from a gun of mass 2kg such that guns recoils with velocity two meter per second the strikes a stationary block of mass 490 gram placed on a rough horizontal surface and gets embidded in it if frictional force provided by the surface on block is 2n the distance travelled by block coming to rest is
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Step-by-step explanation:
Conservation of linear momentum gives,
m
1
v
1
+m
2
v
2
=0
m
1
v
1
=−m
2
v
2
v
1
=
m
1
−m
2
v
2
Given, m
1
=10g=(
1000
10
)kg,
m
2
=1 kg,
v
2
=−5m/s
∴v
1
=
10/1000
+1×5
or v
1
=500m/s.
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