Question

A bullet of mass 10g moving horizontally with a velocity of 150 strikes a stationary wooden block and comes to rest in0.03s calculate

Answer 1

150*10-1500
0.03-1500*0.03-45.00is the answer

Answer 2

Answer:

The distance of penetration of the bullet into the block is 2.25 m.

Explanation:

Given that,

Mass of bullet = 10 g

Initial velocity = 150 m/s

Time = 0.03 sec

Suppose we calculate the distance of penetration of the bullet into the block

We need to calculate the distance of penetration

We know that,

The distance of penetration of the bullet into the block = displacement

Using formula of displacement

$D=\dfrac{v+u}{2}\times t$

Put the value into the formula

$D=\dfrac{150+0}{2}\times0.03$

$D=2.25\ m$

Hence, The distance of penetration of the bullet into the block is 2.25 m.