A bullet of mass 10g moving with a velocity of 400ms get embedded in a freely suspended wooden block of 900g.what is the velocity acquired by block
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Answer:4.39 m/s Explanation: By conservation of momentum, M1v1 + m2v2 = mv ∴0.01 x 400 + 0.9 x 0 = (0.9+0.01) v ∴4 = 0.91 v ∴v = 4.39
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