Question

A bullet of mass 10g moving with a velocity of of 40m/s gas embedded in a freely suspended woods black of mass 0.430g find the velocity occured by the block​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Here is your answer

Step-by-step explanation:

Given

Mass of the Bullet = 0.01 Kg

Initial Velocity = 40 m/s

Final Velocity = ?

Mass of the Block = 0.00043 Kg

Initial Velocity = 0 m/s

Final Velocity

Solution

Using the Law of Conservation

m1u1 + m2u2 = m1v1 + m2v2

0.4 kgms^-2 + 0 = (0.01 + 0.00043 Kg) v2

0.4 kgms^-2 / 0.01043 = v2

38.35 m/s = v2