Question

A bullet of mass 10g moving with velocity 100m/s strikes a mud wall and comes to rest after penetrating through 5m. What is the force offered by the mud wall?

Answer 1

Answer:

10 N

Explanation:

Fs = 1/2 mv^2

5F = 0.5*0.01*10000 = 50

F   = 50/5 = 10 N

Answer 2

The force offered by the mud wall is 10 Newton.

Calculation:

Given that:

Mass of the bullet (m) = 10 g

Converting 10g into kg, we get,

$10 \: g = \frac{10}{1000}$

$10 \: g= 0.01 \: kg$

Velocity of the bullet (v) = 100 m/s

Thickness of the mud (s) = 5 m

To find: Force offered by the mud wall (f)

Let,

the force offered by the mud wall be 'f'

To determine the force offered by the mud wall, we must apply the formula:

$f \: s \: = \frac{m {v}^{2} }{2}$

$f \times 5 = \frac{0.01 \times {100}^{2} }{2}$

$5f = \frac{100}{2}$

$f = \frac{100}{2 \times 5}$

$f = \frac{100}{10}$

$f = 10$

Hence, the force offered by the mud wall is 10 Newton

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