Question

A bullet of mass 10g moving with velocity 100m/s strikes a mud wall and comes to rest after penetrating
through 5m. The force offered by the mud wall is?​

Answer 1

Answer:

20N

Step-by-step explanation:

I guess so if it's not pls forgive me

Answer 2

Answer: 10 N

Step-by-step explanation:

m (mass)= 10g

u (initial velocity)= 100m/s

v (final velocity)= 0m/s (since it comes to rest)

s (distance)= 5m

Using the third equation of motion,

v²-u² =2as

(Substitute the values)

-100² =2a (5)

-10000 = 10a

a = -1000m/s²

Now to find F (Force)

F = ma

(convert mass g to kg)

m= 0.010 kg

(Substitute the values)

F = 0.010×-1000

F  = -10 N

Wall is exerting equal and negative force, i.e., +10 N