A bullet of mass 10g moving with velocity 100m/s strikes a mud wall and comes to rest after penetrating
through 5m. The force offered by the mud wall is?
Answers
Answered by
0
Answer:
20N
Step-by-step explanation:
I guess so if it's not pls forgive me
Answered by
3
Answer: 10 N
Step-by-step explanation:
m (mass)= 10g
u (initial velocity)= 100m/s
v (final velocity)= 0m/s (since it comes to rest)
s (distance)= 5m
Using the third equation of motion,
v²-u² =2as
(Substitute the values)
-100² =2a (5)
-10000 = 10a
a = -1000m/s²
Now to find F (Force)
F = ma
(convert mass g to kg)
m= 0.010 kg
(Substitute the values)
F = 0.010×-1000
F = -10 N
Wall is exerting equal and negative force, i.e., +10 N
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