Question

A bullet of mass 10g moving with velocity 400m/s .gets embedded in a freely suspended wooden block of 900g. what is the velo acquired by the wooden block.
...if you know the answer plz tell me fast.​

Answer 1

Explanation:

By conservation of momentum,

m1u1 + m2u2 = (m1+m2)v

So,

10×400 + 900×0 = (10+900)v

4000 = 910v

So,

v= 400/91 = 4.39m/s

Answer 2

Answer:-

Given:-

Mass (M1) = 10g = 0.01kg

Initial velocity (u1) = 400m/s

Final velocity (v1) = 0

Mass (M2) = 900g = 0.9kg

Initial velocity (u2) = 0

Final velocity (v) = ?

To find:-

Final velocity (v2) of wooden block

By applying law of conservation of momentum,

M1U1+M2U2 = M1V1+M2V2

0.01×400+0.9×0 = 0.01×0+0.9×v2

4+0 = 0+0.9v2

4 = 0.9v2

v2 = 4/0.9

= 4.4444m/s.