Question

a bullet of mass 10g passing through a 10 cm wooden block has its velocity reduced from 100m/s find the average resistance (retardative force ) offered to the bullet .........​

Answer 1

Answer:

Given,

u=300m/s

v=200m/s

s=20cm=0.20m

m=10g=0.01kg

3rd equation of motion,

2as=v^2 −u^2

 retardation, a=−125000m/s^2

 The resistance force, F=ma

F=0.01×125000

F=1250N