A bullet of mass 10g passing through a 10cm wooden block,has its velocity reduce from 100m/s to 50m/s find the average resistance offered to the bullet
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Explanation:
Mass of bullet , m = 10g = 0.01kg
initial velocity, u = 100m/s
final velocity , v = 50m/s
distance travelled , s = 10cm = 0.1m
use formula, v² = u² + 2as
(50)² = (100)² + 2a(0.1)
2500- 10000 = 0.2a
-7500 = 0.2a
a = -37500m/s²
resistance offered by the block = - force exerted by bullet [ from Newton's 3rd law ]
= - mass of bullet × retardation
= -0.01 × -37500 N
= 375N
hence, resistance offered by the block = 375N
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