A bullet of mass 10g traveling horizontally with velocity 150m/s strikes wooden blocks and comes to rest in 3s calculate the distance of penetration of bullet into the block
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Hiii Friend
It can be solve as....
we need the retardation of the bullet which is calculated as-
a=(v-u)/t.
now- t=3s, u=150m/s and final velocity will be zero because bullet come to rest i.e v=0
=> a=-50m/s^2
now we have to calculate S which can be calculated by formula v^2-u^2=2aS.....
from this we get S = (0-150×150)/2×-50
=>S=225m
It can be solve as....
we need the retardation of the bullet which is calculated as-
a=(v-u)/t.
now- t=3s, u=150m/s and final velocity will be zero because bullet come to rest i.e v=0
=> a=-50m/s^2
now we have to calculate S which can be calculated by formula v^2-u^2=2aS.....
from this we get S = (0-150×150)/2×-50
=>S=225m
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