Question

A bullet of mass 10g travelling horizontally with a velocity of 150mls collide with and sticks to a stationary wooden block of mass 5 kg.Then they both move off together in the same straight line. calculate the total momentum just before the impact and just after the impact. also calculate the velocity of the combined objects. ​

Answer 1

Answer:

Initial velocity of the bullet, u=150  ms−1

Final velocity of the bullet, v=0

Mass of the bullet, m=10 g=0.01 kg

Time taken by the bullet to come to rest, t=0.03 s

Let distance of penetration be s

v=u+at

0=150+a(0.03)  

⟹a=−5000 ms−2    (- sign shows retardation)

v2=u2+2as

0=1502+2×(−5000)×s

s=2.25 m

Magnitude of the force exerted by the wooden block, ∣F∣=m∣a∣

∣F∣=0.01×5000=50 N

Explanation:

mark my answer the branliest plz