Question

A bullet of mass 10g travelling horizontally with a velocity of 150 m/s strikes a stationary wooden block and comes to rest in 0.03 sec. Calculate the distance of penetration of the bullet into the

Answer 1

As the bullet with velocity 150 m/s comes to rest in 0.03 seconds, its acceleration
a = v-u / t = 0 - 150 / 0.03 = -5000 m/s^2
Therefore, distance travelled in this time
S = ut + 1/2at^2 = 150*0.03 - (1/2*5000*0.0009) = 4.5 - 2.25 = 2.25 m

The distance of penetration of the bullet into the block is 2.25 m.