Question

A bullet of mass 10g travelling with a speed of 200 m/s penetrates a wooden block of thickness 50 cm which offers a constant resistive force of 200 N to slow down the bullet. Find the speed with which the bullet emerges out of the block.

Answer 1

Answer:

141.4

Explanation:

see the picture and try to solve

Answer 2

The speed with which the bullet emerges out of the block is 0 m/s .

Mass of bullet , m = 10 gm = 0.01 kg .

Speed of bullet , u = 200 m/s .

Thickness of block , d = 0.5 m .

Resistive force , F = 200 N .

We know , F = ma

$a=\dfrac{F}{m}\\\\a=\dfrac{200}{0.01}\\\\a=2\times 10^4\ m/s^2$

Applying equation of motion .

$v^2-u^2=2as\\\\v^2-200^2=-2\times 2\times 10^4\times 0.5\\\\v^2=200^2-200^2\\\\v=0\ m/s$

Hence , this is the required solution .

Learn More :

Kinematics

https://brainly.in/question/15350193