Question

A bullet of mass 10g travelling with a velocity of 150ms Strikes a stationary wooden block and comes to rest in 0.03s calculate the distance of the bullet into the block. Also calculate the magnitude of the farce exerted by the wooden block on the bullet.?



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Answer 1

Let the uniform deceleration of bullet be a as final velocity

v=0,u=150,t=0.03 s

⇒v=u−−at⇒0=150−0.03

⇒a=

0.03

150

=5000 m/sec

2

& S=

2a

v

2

−u

2

=

−2(5000)

−(150)

2

=

100

225

=2.25 m

& F=ma=10×10

−3

×5×10

3

F=50 N

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