Question

A bullet of mass 10gm is moving with 100m/s is embedded in a block of 1kg which is initially at rest the final velocity of the system will be

Answer 1

from law of momentum conservation.

M1V1 + M2V2 = ( M1+M2)V

10×10-³×100 + 0 = (1+0.01)V

V = 1/1.01

V = 100/101 m/s

Answer 2

Answer:1 m/s

Explanation: