A bullet of mass 10gm is moving with 100m/s is embedded in a block of 1kg which is initially at rest the final velocity of the system will be
Answers
Answered by
6
from law of momentum conservation.
M1V1 + M2V2 = ( M1+M2)V
10×10-³×100 + 0 = (1+0.01)V
V = 1/1.01
V = 100/101 m/s
M1V1 + M2V2 = ( M1+M2)V
10×10-³×100 + 0 = (1+0.01)V
V = 1/1.01
V = 100/101 m/s
Answered by
3
Answer:1 m/s
Explanation:
Similar questions
Sociology,
7 months ago
India Languages,
7 months ago
Math,
1 year ago
Social Sciences,
1 year ago
English,
1 year ago