A bullet of mass 10gm moving with a speed of 500 m/s gets embedded in a tree after penetrating 5cm into it. calculate the average retarding force exerted by the wood on the bullet and the work done by the wood in bringing the bullet to stop.
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This is a question on linear motion.
We will use the following equation of linear motion to get acceleration.
v² = u + 2as
Where v = final velocity = 0
u = initial velocity = 500m/ s
a = acceleration.
s = displacement = 5cm
Convert this to meters : 5/100 = 0.05m
Substituting the values into the formulae :
0 = 500 + 2 × 0.05 × a
0 = 500 + 0.1a
- 500 = 0.1 a
a = 500 / 0.1
a = - 5000 m/s² ( the negative sign shows retardation)
Force = Mass × Acceleration
Mass = 10/1000 = 0.01 Kg
F = 5000 × 0.01 = 50N
Work done = Force × displacement
50 × 0.05 = 2.5 Joules.
We will use the following equation of linear motion to get acceleration.
v² = u + 2as
Where v = final velocity = 0
u = initial velocity = 500m/ s
a = acceleration.
s = displacement = 5cm
Convert this to meters : 5/100 = 0.05m
Substituting the values into the formulae :
0 = 500 + 2 × 0.05 × a
0 = 500 + 0.1a
- 500 = 0.1 a
a = 500 / 0.1
a = - 5000 m/s² ( the negative sign shows retardation)
Force = Mass × Acceleration
Mass = 10/1000 = 0.01 Kg
F = 5000 × 0.01 = 50N
Work done = Force × displacement
50 × 0.05 = 2.5 Joules.
Answered by
19
I THINK ANSWER IS
24.87 KN
1250 JOULE (APPROX)
IF ITS RIGHT ANSWER !!
THEN DM ME !
24.87 KN
1250 JOULE (APPROX)
IF ITS RIGHT ANSWER !!
THEN DM ME !
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