a bullet of mass 10gram is fired at a speed of 500m/s from a gun of mass 5kg .what is the recoil velocity of the gun?
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2
According to conservation of momentum
m1v1= m2v2
10*500=5000*v2
V2=1 m/sec
Hope it helps you
m1v1= m2v2
10*500=5000*v2
V2=1 m/sec
Hope it helps you
Answered by
0
You need to apply conservation of linear momentum,
0.01 × 500 = 5 × v
v = 1 m/sec
0.01 × 500 = 5 × v
v = 1 m/sec
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