Question

A bullet of mass 10gram travelling horizontally with a velocity 150 m/s ,strikes a stationary wooden block and comes to rest in 0.03 second. Calculate the distance of penetration of the bullet into the block. Also calculate the magnitude of the force of the force exerted by the wooden block on the bullet.

question for sohan no one else will answer please let him answer first ​

Answer 1

Answer:

Given parameters,

Initial velocity (u) = 150 m/s

Final velocity (v) = 0 (since the bullet finally comes to rest)

Time taken to come to rest (t) = 0.03 s

Find out

The distance of penetration of the bullet into the block. Also the magnitude of the force exerted by the wooden block on the bullet.

Solution

According to the first equation of motion,

v= u + at

Acceleration of the bullet (a)

0 = 150 + (a — 0.03 s)

a = -150 / 0.03

a = – 5000 m/s2

Here the negative sign indicates that the velocity of the bullet is decreasing.

Answer 2

Answer:

ok

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