Question

A bullet of mass 150 gm is moving with a speed of 200 m/s. What is the Kinetic energy of the bullet

Answer 1

Step-by-step explanation:

K. E = 1/2 mv²

So, We have M=150g , V= 200m/s

To find K. E, Lets Use the Formula (K.E= 1/2 mv²)

K. E= 1/2 x 150 x 200 x 200

K. E = 75 x 200 x 200

K. E = 75 x 40000

K. E = 300000 Joules

Hope it helped U