Question

A bullet of mass 1500 gm comes out from the missile tank with a velocity of 200m/s. What is the kinetic energy of the bullet​

Answer 1

Answer:

0.2

Step-by-step explanation:

By the law of conservation of momentum,

Initial momentum = find momentum

∴P1=P2

∴m1v1=m2v2

here, m1=20gm.v1=200ms−1,m2=20kg=20,000gm

∴v2=m2m1v1

=20,00020×200

∴v2=0.2m/s

Answer 2

Answer:

By the law of conservation of momentum,

Initial momentum = find momentum

∴P

1

=P

2

∴m

1

v

1

=m

2

v

2

here, m

1

=20gm.v

1

=200ms

−1

,m

2

=20kg=20,000gm

∴v

2

=

m

2

m

1

v

1

=

20,000

20×200

∴

v

2

=0.2

m/s

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Step-by-step explanation:

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