Question

a bullet of mass 15g is horizontally fired with a velocity 100ms^-1 from a pistol mass 2kg . what is the recoil velocity of the pistol.​

Answer 1

Answer:

$\sf \: By \: momentum \: conservation \: </p><p> \:mBvB=mGvG=0 \\ \\ \sf \: recoil \: velocity \: of \: vG = - \frac{mBvB}{mG} \\ \\ \bf \implies vG = - \frac{ \frac{50}{1000} \times 100}{2} \\ \\ \bf \implies \: vG = 2.5m/s</p><p></p><p>$