Question

A bullet of mass 15g is horizontally fired with velocity 100ms-from a piston of mass 2 kg total momentum of the pistol and bullet before firing is equal to

Answer 1

m1= 15g

u1= 0

v1= 100ms

m2 = 2kg

u2 = 0

v2 = ?

m1u1+m2u2 = m1v1+m2v2

15/1000*0+2*0 = 15/1000*100+2v

0 = 1.5 + 2v

-1.5 = 2v

v = -1.33ms

this is the answer please look at it and mark me as brainliest!!!!!!!