A bullet of mass 15g is horizontally fired with velocity 100ms-from a piston of mass 2 kg total momentum of the pistol and bullet before firing is equal to
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m1= 15g
u1= 0
v1= 100ms
m2 = 2kg
u2 = 0
v2 = ?
m1u1+m2u2 = m1v1+m2v2
15/1000*0+2*0 = 15/1000*100+2v
0 = 1.5 + 2v
-1.5 = 2v
v = -1.33ms
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