a bullet of mass 15g with a moving velocity of 300ms gets embedded in a freely suspended wooden target of mass 735g.calculate the velocity of the target being hit
Answers
Answer:
velocity target being hit =10725
explanation:
first we have to multiply 15 ×735 = 11025
then we have to subtract ; 11025- 300 = 10725
,so the velocity target hit =10725
Answer:
As O is the centre of the circle, AB is the diameter, which can be easily seen from the figure and therefore ∠ACB is a semicircular angle. As we know Semicircular Angles are always Right angles. ∴ The value of x∘ in the following figure is 50∘
Explanation:
please mark it as a brainlist answer please please please please please please please please please please please please please please please pleaseAs O is the centre of the circle, AB is the diameter, which can be easily seen from the figure and therefore ∠ACB is a semicircular angle. As we know Semicircular Angles are always Right angles. ∴ The value of x∘ in the following figure is 50∘