Question

A bullet of mass 20 g is fired from a gun weighing 5 kg. If the velocity of the bullet is
500 ms-l, what will be the speed of the recoiling?​

Answer 1

Let the recoil velocity of gun be V.

Mass of gun Mg =5.0 kg

Mass of bullet Mb =0.01 kg

Velocity of bullet Vb=250 m/s

Initial momentum of the system , Pi =0

Applying the conservation of linear momentum : Pf=Pi

$Mg× V+Mb× Vb=0$

$5×V+0.01×250=0$

$\large\red{\boxed{⟹ V=−0.5 ms^-1}}$

$\large\blue{\underline{\green{\underline{\purple{\mathbb{MARK\:AS\:BRAINLIEST}}}}}}$