Question

A bullet of mass 20 g is horizontally fired with a horizontal velocity 150 ms-1 from a pistol of mass 2 kg. What is the recoil velocity of the pistol?




please do not copy and do not spam.​

Answer 1

Answer:

Hope its help

Explanation:

Sorry for bàd handwriting

Answer 2

⚘ Question:

A bullet of mass 20 g is horizontally fired with a horizontal velocity 150 ms-1 from a pistol of mass 2 kg. What is the recoil velocity of the pistol?

⚘ Answer:

Bullet (first body)

⇢m₁ = 20g (20/1000) = 0.02kg

⇢u₁ = 0

⇢v₁ = 150m/s

Pistol (second body)

⇢m₂ = 2kg

⇢u₂ = 0

⇢v₂ = ? (recoil velocity)

According to law of conservation of momentum, m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

➺ (0.02×0) + (2×0) = (0.02×150) + (2v₂)

➺ 0 = 3 + 2v₂

➺ 2v₂ = -3

➺ v₂ = -3/2

➺ v₂ = -1.5 m/s

Therefore the recoil velocity = -1.5m/s

Here the negative sign indicates that the direction in which the the pistol would recoil is opposite to that of the bullet.