Science, asked by YuchangpilaSangtam, 7 months ago

A bullet of mass 20 g is
horizontally fired with a velocity
150 m s-1 from a pistol of mass 2 kg.
What is the recoil velocity of the pistol?​

Answers

Answered by Anonymous
1

mass of bullet=20gm

=20gm/1000

=0.02kg

initial velocity of bullet =0 m/s

final velocity of bullet =150 m/s

mass of pistol =2kg

final velocity of pistol =?

initial velocity of pistol =0

according to conservation of momentum

m1u1 + m2u2 = m1v1 + m2v2

[0.02] 0 +(2)0 = [0.02]150+2v

0 = 3+2v^2

3+2v^2=0

2v^2 = -3

v^2 = -3/2

v^2 = -1.5 m/s

PLZZZ TAG AS BRAINLIST

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