A bullet of mass 20 g is
horizontally fired with a velocity
150 m s-1 from a pistol of mass 2 kg.
What is the recoil velocity of the pistol?
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mass of bullet=20gm
=20gm/1000
=0.02kg
initial velocity of bullet =0 m/s
final velocity of bullet =150 m/s
mass of pistol =2kg
final velocity of pistol =?
initial velocity of pistol =0
according to conservation of momentum
m1u1 + m2u2 = m1v1 + m2v2
[0.02] 0 +(2)0 = [0.02]150+2v
0 = 3+2v^2
3+2v^2=0
2v^2 = -3
v^2 = -3/2
v^2 = -1.5 m/s
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