A bullet of mass 20 g is horizontally fired with a velocity 150 m s¹ from a pistol of mass 2 kg. What is the recoil velocity of the pistol?
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Answer:
The recoil velocity of the pistol is 1.5 m/s.
Step-by-step explanation:
Given :
A bullet of mass 20 g is horizontally fired with a velocity 150 m/s from a pistol of mass 2 kg.
To find :
the recoil velocity of the pistol.
Solution :
Mass of the bullet, m = 20 g = 0.02 kg
Mass of the pistol, M = 2 kg
Velocity of the bullet, v = 150 m/s
Velocity of the pistol, V = ?
Initial momentum of the system = 0 (rest)
Final momentum of the system = mv + MV
By the law of conservation of momentum,
Initial momentum = Final momentum
0 = mu + MV
0 = 0.02(150) + 2V
2V = –3
V = –1.5 m/s
Therefore, the recoil velocity of the pistol is 1.5 m/s.
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