a bullet of mass 20 g is horizontally fired with a velocity 150 metre per second from a pistol of mass 2 kg what is the recoil velocity of the pistol?
a. 1.5 m/s
b. -1.5m/s
c. 150 m/s
d. -150 m/s
Answers
Answered by
0
Answer:
a.
Explanation:
1.5 m/s
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Answered by
0
Answer:
according to law of conservation of momentum
m1v1+m2v2=m1v1'+m2v2'
Explanation:
0.02×0+2×0=0.02×150+2×v2'
0=3+2v2'
2v2'=-3
v2'=-3/2
v2'=-1.5
Hence correct answer is option B
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