A bullet of mass 20 g moving with a speed of 500 m/s strikes a wooden block of mass 1 kg and gets embedded in it. Find the speed with which block moves along with the bullet.
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m1 = 20g = 0.020kg
v1 = 500m/s
m2 = 1kg
v2 = ?
m1v1 = m2v2
0.02 × 500 = (1 + 0.02) v2
10 = 1.02v2
10 / 1.02 = v2
v2 = 9.80m/s
Thanks
v1 = 500m/s
m2 = 1kg
v2 = ?
m1v1 = m2v2
0.02 × 500 = (1 + 0.02) v2
10 = 1.02v2
10 / 1.02 = v2
v2 = 9.80m/s
Thanks
Answered by
0
use that formula u got ans
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